9p^2+p-17=-10

Solution for 9p^2+p-17=-10 equation:

9p^2+p-17=-10

We move all terms to the left:

9p^2+p-17-(-10)=0

We add all the numbers together, and all the variables

9p^2+p-7=0

a = 9; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·9·(-7)
Δ = 253
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{253}}{2*9}=\frac{-1-\sqrt{253}}{18}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{253}}{2*9}=\frac{-1+\sqrt{253}}{18}
$